Question

Bỏ dấu ngoặc rồi tính :

a) \(\left(27+65\right)+\left(346-27-65\right)\)

b) \(\left(42-69+17\right)-\left(42+17\right)\)

Answer 1

a) (27+65)+(346-27-65)

= 27+65+346-27-65

= (27-27)+(65-65)+346

= 0 + 0 + 346

= 346

b) (42-69+17)-(42+17)

= 42-69+17 – 42 – 17

= (42-42)+(17-17)-69

= 0 + 0 – 69

= -69

Answer 2

a)(27+65)+(346-27-65)

=27+65+345-27-65

=(27-27)+(65-65)+346

=0+0+346

=346

b) (42-69+17)-(42+17)

=42-69+17-42-17

=(42-42)-69+(17-17)

=0-69+0

=-69

Answer 3

a)(27+65)+(346-27-65)

=27+65+346-27-65

=92+346-27-65

=438-27-65

=411-65

=346

b)(42-69+17)-(42+17)

=42-69+17-42+17

=-27+17-42+17

=-10-42+17

=-52+17

=-35

Answer 4

a)(27+65)+(346-27-65)=27+65+346-27-65=(27-27)+(65-65)+346=346

b)(42-69+17)-(42+17)=42-69+17-42-17=42+(-69)+17+(-42)+(-17)=42+(-42)+17+(-17)+(-69)=-69

Answer 5

a) (27+65)+(346-27-65)=27+65+346-27-65

=(27-27)+(65-65)+346=0+0+346=346

b) (42-69+17)-(42+17)=42-69+17-42-17

=(42-42)+(17-17)-69=0+0-69=-69

Answer 6

a)

= (27-27)+(65-65)+346

= 0 + 0 +346

= 346

b)