\(a.\) \(\left(-\dfrac{3}{4}\right)+\dfrac{2}{7}+\left(-\dfrac{1}{4}\right)+\dfrac{3}{5}+\dfrac{5}{7}\)
= \(\left[\left(-\dfrac{3}{4}\right)+\left(-\dfrac{1}{4}\right)\right]+\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\dfrac{3}{5}\)
= \(\left(-1\right)+1+\dfrac{3}{5}\)
= \(\dfrac{3}{5}\)