bài 1
a,frac{x}{5}frac{2}{3}
b,frac{x}{3}-frac{1}{2}frac{1}{5}
c,frac{x}{5}+frac{1}{2}frac{6}{10}
d,frac{x+3}{15}frac{1}{3}
e,frac{x-12}{4}frac{1}{2}
h,frac{4}{5}+xfrac{2}{3}
i,frac{3}{4}-xfrac{1}{3}
k,frac{-5}{6}-xfrac{2}{3}
l,x-frac{5}{9}frac{-2}{3}
m,frac{1}{2}x+frac{1}{2}frac{5}{2}
n,frac{-2}{3}-frac{1}{3}(2x-5)frac{3}{2}
p,(3x-1)(-frac{1}{2}x+5)0
q,3frac{1}{3}+frac{5}{6}x3frac{1}{2}
s,frac{1}{2}-frac{2}{3}xfrac{7}{12}
t,frac{3}{4}x+frac{1}{5}frac{1}{6}
u,frac{3}{8}-frac{1}{...
Đọc tiếp
bài 1
a,\(\frac{x}{5}\)=\(\frac{2}{3}\)
b,\(\frac{x}{3}\)-\(\frac{1}{2}\)=\(\frac{1}{5}\)
c,\(\frac{x}{5}\)+\(\frac{1}{2}\)=\(\frac{6}{10}\)
d,\(\frac{x+3}{15}\)=\(\frac{1}{3}\)
e,\(\frac{x-12}{4}\)=\(\frac{1}{2}\)
h,\(\frac{4}{5}\)+x=\(\frac{2}{3}\)
i,\(\frac{3}{4}\)-x=\(\frac{1}{3}\)
k,\(\frac{-5}{6}\)-x=\(\frac{2}{3}\)
l,x-\(\frac{5}{9}\)=\(\frac{-2}{3}\)
m,\(\frac{1}{2}\)x+\(\frac{1}{2}\)=\(\frac{5}{2}\)
n,\(\frac{-2}{3}\)-\(\frac{1}{3}\)(2x-5)=\(\frac{3}{2}\)
p,(3x-1)(\(-\frac{1}{2}\)x+5)=0
q,\(3\frac{1}{3}\)+\(\frac{5}{6}\)x=\(3\frac{1}{2}\)
s,\(\frac{1}{2}\)-\(\frac{2}{3}\)x=\(\frac{7}{12}\)
t,\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)
u,\(\frac{3}{8}\)-\(\frac{1}{6}\)x=\(\frac{1}{4}\)
mn ơi'-' xin hãy giúp mk với ạ>^<,mk cần rất gấp,mai nộp r ạ,mong mn giúp mk với ạ:(( huhuhu r mk tik cho:<<
