A = \(\dfrac{1}{4}.\dfrac{7}{3}.12\)
= \(\dfrac{1.7.12}{4.3}\)
= \(7\)
@Nguyễn Thành Đăng
B = \(\dfrac{3}{8}.56.\dfrac{25}{7}.\left(-4\right)\)
= \(-\dfrac{3.56.25.4}{8.7}\)
= -3.100
= -300
@Nguyễn Thành Đăng
C = \(\dfrac{6}{7}.\dfrac{8}{13}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{3}{13}.\dfrac{6}{7}\)
= \(\dfrac{8}{7}.\dfrac{6}{13}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{6}{13}.\dfrac{3}{7}\)
= \(\dfrac{6}{13}\left(\dfrac{8}{7}+\dfrac{9}{7}-\dfrac{3}{7}\right)\)
= \(\dfrac{6}{13}\left(\dfrac{8+9-3}{7}\right)\)
= \(\dfrac{6}{13}.2\)
= \(\dfrac{12}{13}\)
@Nguyễn Thành Đăng
D = \(\dfrac{-1}{4}.\dfrac{152}{11}+\dfrac{68}{4}.\dfrac{-1}{11}\)
= \(\dfrac{1}{4}.\dfrac{152}{11}+\dfrac{1}{4}.\dfrac{68}{11}\)
= \(\dfrac{1}{4}\left(\dfrac{152}{11}+\dfrac{68}{11}\right)\)
= \(\dfrac{1}{4}.20\)
= 5
@Nguyễn Thành Đăng
Nguyễn Huy Tú , Trần Đăng Nhất , Toshiro Kiyoshi , Hồng Phúc Nguyễn : giúp mik với