a/ \(\dfrac{49}{5}-\left(\dfrac{8}{3}+\dfrac{34}{5}\right)\)=\(\dfrac{49}{5}-\left(\dfrac{40}{15}+\dfrac{102}{15}\right)=\dfrac{49}{5}-\dfrac{142}{15}\)
=\(\dfrac{147}{15}-\dfrac{142}{15}=\dfrac{1}{3}\)
b/\(\dfrac{3}{4}-\dfrac{13}{10}+\dfrac{1}{2}:\dfrac{5}{8}\)=\(\dfrac{3}{4}-\dfrac{13}{10}+\dfrac{1}{2}.\dfrac{8}{5}\)
=\(\dfrac{3}{4}-\dfrac{13}{10}+\dfrac{4}{5}\)
=\(\dfrac{15}{20}-\dfrac{26}{20}+\dfrac{16}{20}\)
=\(\dfrac{1}{4}\)
Chúc bạn học tốt!