Question

bài 1:

a) \(\dfrac{x}{17}\)+\(\dfrac{9}{34}\)=1

b) \(\dfrac{11}{12}\) - (\(\dfrac{2}{5}\)+x)=\(\dfrac{2}{3}\)

Answer 1

\(a.\dfrac{x}{17}+\dfrac{9}{34}=1\)

\(\Leftrightarrow\dfrac{x}{17}=1-\dfrac{9}{34}\)

\(\Leftrightarrow\dfrac{x}{17}=\dfrac{25}{34}\)

\(\Leftrightarrow34x=17.25\)

\(\Leftrightarrow34x=425\)

\(\Leftrightarrow x=\dfrac{425}{34}\)

Vậy ......

b. \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)

\(\dfrac{2}{5}+x=\dfrac{11}{12}-\dfrac{2}{3}\)

\(\dfrac{2}{5}+x=\dfrac{1}{4}\)

\(x=\dfrac{1}{4}-\dfrac{2}{5}\)

\(x=\dfrac{-3}{20}\)

Vậy .....