Question

bài 1:

a, (1-\(\frac{3}{6}\)²)+/\(\frac{-7}{23}\)/+(-\(\frac{4}{25}\))

b, \(\sqrt{25}\)-\(\sqrt{100}\)+\(\sqrt{36}\)

c,(\(\frac{-31}{37}\))⁵.(\(\frac{37}{62}\))⁵

bài 2:

a,(x-\(\frac{3}{5}\))²=4

b,2^x+2^x+3=144

xg trc tick cho

Answer 1

khó quá bn ơi

Answer 2

2b,

Answer 3

a)\(\left(1-\frac{3}{6}^2\right)+\left|\frac{-7}{23}\right|+\left(-\frac{4}{25}\right)\\ =\frac{3}{4}+\frac{7}{23}+\left(-\frac{4}{25}\right)\\ =\frac{2057}{2300}\)

b)\(\sqrt[]{25}-\sqrt[]{100}+\sqrt[]{36}\\ =5-10+6\\ =1\)

c)\(\left(\frac{-31}{37}\right)^5.\left(\frac{37}{62}\right)^5\\ =\left(\frac{-31}{37}.\frac{37}{62}\right)^5\\ =\left(\frac{-1}{2}\right)^2\\ =\frac{1}{4}\)

Answer 4

a)\(\left(x-\frac{3}{5}\right)^2=4\\ \left(x-\frac{3}{5}\right)^2=2^2\\ \Rightarrow\left\{{}\begin{matrix}x-\frac{3}{5}=2\\x-\frac{3}{5}=-2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\frac{13}{5}\\\frac{-7}{5}\end{matrix}\right.\)

vậy \(x=\left\{\frac{13}{5};\frac{-7}{5}\right\}\)

b) câu này bạn kia lm r

Answer 5

làm sao bạn viết được phân số vậy chỉ mình với