A<B. vi 10A=1+14/15mu17 +1
10B=1+14/15mu 16+1
suy ra 10A<10B suy ra A<B
Ta có: \(15A=\frac{15^{17}+15}{15^{17}+1}=1+\frac{14}{15^{17}+1}\)
\(15B=\frac{15^{16}+15}{15^{16}+1}=1+\frac{14}{15^{16}+1}\)
Vì \(\frac{14}{15^{17}+1}< \frac{14}{15^{16}+1}\Rightarrow1+\frac{14}{15^{17}+1}< 1+\frac{14}{15^{17}+1}\)
\(\Rightarrow15A< 15B\)
\(\Rightarrow A< B\)
Vậy A < B
mk thiếu :
vì 10A= 1+14/15 mũ 17 +1
10B=1+14/15 mũ 16 +1