\(\left(\dfrac{3}{10}+\dfrac{4}{5}\cdot\dfrac{1}{2}\right):\left(\dfrac{18}{9}-1\dfrac{1}{3}\right)\)
\(=\left(\dfrac{3}{10}+\dfrac{4}{10}\right):\left(\dfrac{6}{3}-\dfrac{4}{3}\right)\)
\(=\dfrac{7}{10}:\dfrac{2}{3}=\dfrac{7}{10}\cdot\dfrac{3}{2}=\dfrac{21}{20}\)