Giải:
\(a,27^3:3^2.\)
\(=\left(3^3\right)^3:\left(3^1\right)^2.\)
\(=3^9:3^2.\)
\(=3^{9-2}=3^7.\)
Vậy.....
\(b,\left(\dfrac{3}{5}\right)^{13}:\left(\dfrac{9}{25}\right)^5.\)
\(=\left(\dfrac{3}{5}\right)^{13}:\left[\left(\dfrac{3}{5}\right)^2\right]^5.\)
\(=\left(\dfrac{3}{5}\right)^{13}:\left(\dfrac{3}{5}\right)^{10}.\)
\(=\left(\dfrac{3}{5}\right)^{13-10}.\)
\(=\left(\dfrac{3}{5}\right)^3.\)
Vậy.....
~ Hok tốt!!! ~ =))
Bài làm
a, 273 : 32
= (33)3 : 32
= 39 : 32
= 37
Vậy ....
b, \(\left(\dfrac{3}{5}\right)^{13}:\left(\dfrac{9}{25}\right)^5\)
= \(\left(\dfrac{3}{5}\right)^{13}:\left[\left(\dfrac{3}{5}\right)^2\right]^5\)
= \(\left(\dfrac{3}{5}\right)^{13}:\left(\dfrac{3}{5}\right)^{10}\)
= \(\left(\dfrac{3}{5}\right)^3\)
Vậy ...
a) 273:32=(33)3 :32=39:32=37=2187 b)\(\left(\dfrac{3}{5^{ }}\right)^{13}:\left(\dfrac{9}{25}\right)^5\) =\(\left(\dfrac{3}{5}\right)^{13}:\left(\dfrac{3}{5}\right)^{10}=\left(\dfrac{3}{5}\right)^3=\dfrac{27}{125}\)
