\(\left[\left(8x-12\right):4\right].27=36\)
\(\Rightarrow\left[\left(8x-12\right):4\right]=36:27=\dfrac{4}{3}\)
\(\Rightarrow\left(8x-12\right)=\dfrac{4}{3}.4=\dfrac{16}{3}\)
\(\Rightarrow8x=\dfrac{16}{3}+12=\dfrac{52}{3}\)
\(\Rightarrow x=\dfrac{52}{3}:8=\dfrac{13}{6}\)
Vậy........
(8.x-12):4=\(\dfrac{4}{3}\)
8x-12=\(\dfrac{16}{3}\)
8x=\(\dfrac{52}{3}\)
x=\(\dfrac{13}{6}\)
\(\left[\left(8x-14\right):4\right].27=36\)
\(\Leftrightarrow\left[\left(8x-14\right):4\right]=36:27\)
\(\Leftrightarrow\left[\left(8x-14\right):4\right]=\dfrac{4}{3}\)
\(\Leftrightarrow8x-14=\dfrac{4}{3}.4\)
\(\Leftrightarrow8x-14=\dfrac{16}{3}\)
\(\Leftrightarrow8x=\dfrac{16}{3}+14\)
\(\Leftrightarrow8x=\dfrac{58}{3}\)
\(\Leftrightarrow x=\dfrac{29}{12}\)
[ ( 8 . x - 12 ) : 4 ] . 27 = 36
[ ( 8 . x - 12 ) : 4 ] = 36 : 27
[ ( 8 . x - 12 ) : 4 ] = 4/3
( 8 . x - 12 ) = 4/3 . 4
( 8 . x - 12 ) = 16/3
8 . x = 16/3 + 12
8 . x = 52/3
x = 52/3 : 8
x = 13/6
Vậy x = 13/6
[(8x - 12) : 4] . 27 = 36
=> (8x - 12) : 4 = \(\dfrac{36}{27}=\dfrac{4}{3}\)
=> 8x - 12 = \(\dfrac{4}{3}.4=\dfrac{16}{3}\)
=> 8x = \(\dfrac{16}{3}+12=\dfrac{16}{3}+\dfrac{36}{3}=\dfrac{52}{3}\)
=> x = \(\dfrac{52}{3}:8=\dfrac{52}{3}.\dfrac{1}{8}=\dfrac{52}{24}\)\(=\dfrac{13}{6}\)