Ta có: \(6\frac{3}{5}-\left(1\frac{2}{3}+2\frac{3}{5}\right)=6\frac{3}{5}-2\frac{3}{5}-1\frac{2}{3}\)
\(=6+\frac{3}{5}-2-\frac{3}{5}-1-\frac{2}{3}\)
\(=\left(6-2-1\right)+\left(\frac{3}{5}-\frac{3}{5}-\frac{2}{3}\right)\)
\(=3-\frac{2}{3}=\frac{7}{3}\)