Question

67,6:\(\dfrac{\dfrac{2}{5}\times x+3}{20+9.5}=\dfrac{132}{5}\)

Answer 1

\(67,6:\dfrac{\dfrac{2}{5}x+3}{20+9.5}=\dfrac{132}{5}\)

\(\Rightarrow\dfrac{\dfrac{2}{5}x+3}{45}=67,6:\dfrac{132}{5}\)

\(\Rightarrow\dfrac{\dfrac{2}{5}x+3}{65}=\dfrac{169}{66}\)

\(\Rightarrow\left(\dfrac{2}{5}x+3\right).66=132.65\)

\(\Rightarrow\dfrac{2}{5}x+3=\dfrac{10985}{66}\)

\(\Rightarrow\dfrac{2}{5}x=\dfrac{10985}{66}-3=\dfrac{10787}{66}\)

\(\Rightarrow x=\dfrac{10787}{66}:\dfrac{2}{5}=\dfrac{53935}{132}\)

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Answer 2

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