\(5\cdot\left(3x-x\right)-7\cdot\left(x+3\right)=8\cdot\left(3-x\right)\)
= \(5.2x-7x-21=24-8x\)
= \(10x-7x+8x=24+21\)
= \(11x=45\)
-> \(x=\frac{45}{11}\)
5(3x-x)-7(x+3)=8(3-x)
<=>5.2x-7x-21=24-8x
<=>10x-7x-21=24-8x
<=>3x-21=24-8x
<=>3x+8x=24+21
<=>11x=45
mà 45 không chia hết cho 11 nên x thuộc rỗng
5(3x-x)-7(x+3)=8(3-x) <=> 5.2x-7x-21=24-8x <=> 10x-7x+8x=21+24 <=> 11x=45 <=> x=45/11 Vậy x=45/11