\(|3x-1|-2x=5+3x\)
\(\Rightarrow|3x-1|=5+5x\)
\(\Rightarrow3x-1=\pm5x+5\)
\(+3x-1=-5x+5\)
\(\Rightarrow3x=-5x+6\)
\(\Rightarrow3x-6=-5x\)\(\)
\(\Rightarrow6=-2x\)
\(\Rightarrow-3=x\)
\(+3x-1=5x+5\)
\(\Rightarrow3x=5x+6\)(vô lý)
\(\Rightarrow x=-3\)
k mik nha
|3x-1|-2x=5+3x
<=>|3x-1|=5+3x+2x
<=>|3x-1|=5+5x
<=>\(\left[{}\begin{matrix}3x-1=5+5x\\3x-1=-\left(5+5x\right)\end{matrix}\right.< =>\left[{}\begin{matrix}3x-5x=5+1\\3x+5x=-5+1\end{matrix}\right.\)
<=>\(\left[{}\begin{matrix}-2x=6\\8x=-4\end{matrix}\right.< =>\left[{}\begin{matrix}x=-3\\x=-\dfrac{1}{2}\end{matrix}\right.\)
Xong rồi đó! cho mk 1 tk nhé
Giải:
\(\left|3x-1\right|-2x=5+3x\)
\(\Leftrightarrow\left|3x-1\right|=5+3x+2x\)
\(\Leftrightarrow\left|3x-1\right|=5+5x\)
Xét các trường hợp:
* \(3x-1=5+5x\)
\(\Leftrightarrow3x-5x=5+1\)
\(\Leftrightarrow-2x=6\)
\(\Leftrightarrow x=-3\)
* \(3x-1=-\left(5+5x\right)\)
\(\Leftrightarrow3x-1=-5-5x\)
\(\Leftrightarrow3x+5x=-5+1\)
\(\Leftrightarrow8x=-4\)
\(\Leftrightarrow x=-\dfrac{1}{2}\)
Vậy ...
Ai làm xong trước mình tk cho!!
