Ta có : \(3a+5⋮2a+1\)
\(\Rightarrow6a+10⋮2a+1\)
\(\Rightarrow6a+3+7⋮2a+1\)
\(\Rightarrow3\left(2a+1\right)+7⋮2a+1\)
Thấy : \(3\left(2a+1\right)⋮2a+1\)
\(\Rightarrow7⋮2a+1\)
- Để thỏa mãn yêu cầu đề bài \(\Leftrightarrow2a+1\inƯ_{\left(7\right)}\)
\(\Leftrightarrow2a+1\in\left\{1;-1;7;-7\right\}\)
\(\Leftrightarrow x\in\left\{0;-1;3;-4\right\}\)
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