(3,5+2x)\(\times\dfrac{8}{3}=5\dfrac{1}{3}\)
=\(\left(\dfrac{7}{2}+2x\right)\times\dfrac{8}{3}=\dfrac{16}{3}\)
=\(\dfrac{7}{2}\times\dfrac{8}{3}+2x\times\dfrac{8}{3}=\dfrac{16}{3}\)
\(2x\times\dfrac{8}{3}=\dfrac{16}{3}-\dfrac{7}{2}\times\dfrac{8}{3}\)
\(2x\times\dfrac{8}{3}=-4\)
\(2x=-4:\dfrac{8}{3}\)
\(2x=\dfrac{-3}{2}\)
\(x=\dfrac{-3}{2}:2\)
\(x=\dfrac{-3}{4}\)
\(\left(3.5+2x\right)\times\dfrac{8}{3}=5\dfrac{1}{3}\)
\(\Rightarrow\left(3.5+2x\right)=\dfrac{16}{3}\times\dfrac{8}{3}=\dfrac{128}{9}\)
\(\Rightarrow2x=\dfrac{128}{9}-3.5\)