\(\Leftrightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Leftrightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Leftrightarrow\frac{-3}{2}x=\frac{-23}{4}\)
\(\Leftrightarrow x=\frac{23}{6}\)
\(\Leftrightarrow\frac{3}{4}x-\frac{1}{4}=2x-6+\frac{1}{4}x\)
\(\Leftrightarrow\frac{3}{4}x-2x-\frac{1}{4}x=-6+\frac{1}{4}\)
\(\Leftrightarrow\frac{-3}{2}x=\frac{-23}{4}\)
\(\Leftrightarrow x=\frac{23}{6}\)
1)6x-8=3x+1
2)12-10x=25-30x
3)3(2x+3)-2(4x-5)=10x+21
4)5(5x-3)-3(2x-4)11-5x
5)4(2-3x)-5(1-2x)=4-6x
6)8(4x-3)-3(2-3x)=13-40x
7)10x-5(1-4x)=5x-11
8)-3(3-4x)-5(4-3x)=12x-50
9)-2(20x-3)-3(4x-5)=9-2(2x-3)
10)-5(2-3x)+3(5-2x)=3x+3(3-5x)
1)8(4x-3)-3(2-3x)=13-40x
2)10x-5(1-4x)=5x-11
3)-3(3-4x)-5(4-3x)=12x-50
1) 3(x-5)(2x+9)+3x-15=0
2) (x2-16)(12-4x)=0
3) (9-x2)(4x-8)=0
4) (8-x3)(5x-125)=0
5) 4x=8
Bài 1: Tìm x biết :
a) (x+2)^2 - (3x-7)^2=0
b) (4x+1) -(5x-3)^2=0
c) 25(x-3)^2 - 49(2x+1)^2=0
d) 9(3x-2)^2=121(1-4x)^2
e) (x-5/4)^2=(5x+1/2)^2
(4x-1)(4x-1)^2-(4x-3)(16x^2+3) Ko phụ thuộc vào biến !!
Tìm x
A)3x/5=1-4x/3
B)x/5=15/3x
C)4(x+2)^3=4/343
1) 4x-(2x-5)=21
2) 14x+5=8x+10
3) 15+5x=3x+30
4) 2x-5=15-3x
5) 2(3x+5)+3(x+1)=6x+20
6) 4(x-3)+5(x-3)=18
1/ \(|\)x+1\(|\) + \(|\)x - 4\(|\) + \(|\)x + 2\(|\) = 4x - 16
2/ \(|x-1|+|x-2|+|x-3|\)= 4x - 12
3/ \(|x+2|+|x+3|\)= x
Bài 1: Tìm x
a) \(\left(\frac{1}{8}\right)^x.27^{2.x}=\left(-9\right)^4\)
b) \(5^x\left(5^3\right)^2=625\)
c)\(\left(4x-1\right)^{30}=\left(4x-1\right)^{20}\)