Question

( -3 ) . (2 . y + 1 ) = 7

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Answer 1

\(\text{( -3 ) . (2 . y + 1 ) = 7}\)

\(\Rightarrow\left(2.y+1\right)=7\div\left(-3\right)\)

\(\Leftrightarrow\left(2.y+1\right)=\left(-2,3\right)\)

\(\Rightarrow2.y=\left(-2,3\right)-1\)

\(\Leftrightarrow2.y=\left(-3,3\right)\)

\(\Rightarrow\)\(y=\left(-3,3\right)\div2\)

\(\Rightarrow y=1,6\)

Answer 2

\(2.y+1=\frac{-7}{3}\)

\(2.y=\frac{-7}{3}+1=\frac{-4}{3}\)

\(y=\frac{-4}{3}:2=\frac{-4}{6}=\frac{-2}{3}\)

Answer 3