Theo đề ta có:
(2x+5).|-7|=73
=> \(\left[{}\begin{matrix}\left(2x+5\right).7=73\\\Rightarrow\left(2x+5\right)=\dfrac{73}{7}\\\Rightarrow2x=\dfrac{73}{7}-5\\\Rightarrow2x=\dfrac{73}{7}-\dfrac{35}{7}\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}2x=\dfrac{38}{7}\\\Rightarrow x=\dfrac{38}{7}:2\\\Rightarrow x=\dfrac{19}{7}\end{matrix}\right.\)
Ta có : (2.x + 5) .|-7 | = 73
=> (2.x + 5 ) . 7 = 73
=> (2.x + 5 ) = 73 / 7
=> 2x = \(\dfrac{73}{7}\) - 5
=> 2x = 38 / 7
=> x = 38 / 7 : 2
=> x = 19/7