Question

-2/3  mũ 2018 nhân 3/2 mũ 2020

Answer 1

`(-2/3)^2018*(3/2)^2020`

`=(2/3)^2018*(3/2)^2018*(3/2)^2`

`=(2/3*3/2)^2018*9/4`

`=1*9/4=9/4`

Answer 2

\(\left(\dfrac{-2}{3}\right)^{2018}\).\(\left(\dfrac{3}{2}\right)^{2020}\)=\(\left(\dfrac{-2}{3}\right)^{2018}\).\(\left(\dfrac{3}{2}\right)^{2018}\).\(\left(\dfrac{3}{2}\right)^2\)=\(\left(\dfrac{-2}{3}.\dfrac{3}{2}\right)^{2018}\).\(\dfrac{9}{4}\)=-1.\(\dfrac{9}{4}\)=\(\dfrac{-9}{4}\)

Answer 3

Tham khảo:

-\(\dfrac{2}{3}\)²⁰¹⁸\(\times\)\(\dfrac{3}{2}\)²⁰²⁰

=-\(\dfrac{2^{2018}\times3^{2020}}{3^{2018}\times2^{2020}}\)

=-\(\dfrac{3^2}{2^2}\)=-\(\dfrac{9}{4}\)

Chúc bạn học tốt.

Answer 4

Giải:

\(\left(\dfrac{-2}{3}\right)^{2018}.\left(\dfrac{3}{2}\right)^{2020}\) 

\(=\left(\dfrac{-2}{3}\right)^{2018}.\left(\dfrac{3}{2}\right)^{2020}\) 

\(=\left(\dfrac{-2}{3}\right)^{2018}.\left(\dfrac{3}{2}\right)^{2018}.\left(\dfrac{3}{2}\right)^2\) 

\(=\left(\dfrac{-2}{3}.\dfrac{3}{2}\right)^{2018}.\dfrac{9}{4}\) 

\(=\left(-1\right)^{2018}.\dfrac{9}{4}\) 

\(=1.\dfrac{9}{4}\) 

\(=\dfrac{9}{4}\) 

Chúc bạn học tốt!