\(2\left(x+3\right)+3\left(2+x\right)=62\\ 2x+6+6+3x=62\\ 5x+12=62\\ \Rightarrow5x=50\\ \Rightarrow x=10\)
Vậy x = 10
2(x+3)+3(2+x)=62
2x+6+6+3x=62
5x+12=62
⇒5x=50
⇒x=10
2.[x+3]+3.[2+x]=62
2x+6+6+3x=62
(2x+3x)+(6+6)=62
5x + 12 =62
5x = 62-12
5x = 50
x = 50:5
x = 10
2. ( x+ 3) + 3 . ( 2+x) = 62
2x+ 6+ 6+ 3x = 62
2x+ 3x = -6 - 6+ 62
5x = 50
x = 50: 5
x = 1