Question

1.(x+1/3)^2=16

2.x+3/10=7/5

Answer 1

1.

\(\left(x+\dfrac{1}{3}\right)^2=16\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=4\\x+\dfrac{1}{3}=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{3}\\x=\dfrac{-13}{3}\end{matrix}\right.\)

2.

\(x+\dfrac{3}{10}=\dfrac{7}{5}\\ x=\dfrac{7}{5}-\dfrac{3}{10}\\ x=\dfrac{11}{10}\)

Answer 2

\(\left(x+\dfrac{1}{3}\right)^2=16\)

\(\left[{}\begin{matrix}\left(x+\dfrac{1}{3}\right)^2=4^2\\\left(x+\dfrac{1}{3}\right)^2=\left(-4\right)^2\end{matrix}\right.\)

\(\left[{}\begin{matrix}x+\dfrac{1}{3}=4\\x+\dfrac{1}{3}=-4\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=4-\dfrac{1}{3}\\x=-4-\dfrac{1}{3}\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=\dfrac{11}{3}\\x=\dfrac{-13}{3}\end{matrix}\right.\)

Answer 3

\(x+\dfrac{3}{10}=\dfrac{7}{5}\)

\(x=\dfrac{7}{5}-\dfrac{3}{10}\)

\(x=\dfrac{14}{10}-\dfrac{3}{10}\)

\(x=\dfrac{11}{10}\)

Vậy x = \(\dfrac{11}{10}\)