Question

1.viết tích sau dưới dạng 1 lũy thừa

\(7^2\cdot49^3\cdot7^7\)

\(3^5\cdot9^4\cdot27^2\cdot81\)

Answer 1

\(7^2.49^3.7^7=7^2.\left(7^2\right)^3.7^7=7^2.7^6.7^7=7^{15}\)

\(3^5.9^4.27^2.81=3^5.\left(3^2\right)^4.\left(3^3\right)^2.3^4=3^5.3^8.3^6.3^4=3^{23}\)

Answer 2

a) \(7^2.49^3.7^7=7^2.7^6.7^7=7^{15}\)

b) \(3^5.9^4.27^2.81=3^5.3^8.3^6.3^4=3^{23}\)

Answer 3

\(7^2.49^3.7^7\)

= \(7^7.\left(7^2\right)^3.7^7\)

= \(7^7.7^6.7^7\)

= \(7^{7+6+7}\)
= \(7^{20}\)

\(3^5.9^4.27^2.81\)

= \(3^5.\left(3^2\right)^4.27^2.81\)

= \(3^2.3^8.\left(3^6\right)^2.3^3\)

= \(3^2.3^8.3^{12}.3^3\)

= \(3^{2+8+12+3}\)

= \(3^{25}\)