Câu hỏi của Jang Mi

Question

1/2.x+3/5.(x-2)=3

Luong Gia Khiem · Accepted Answer

$\dfrac{1}{2}x+\dfrac{3}{5}\left(x-2\right)=3$

$\dfrac{1}{2}x+\dfrac{3}{5}.x-\dfrac{3}{5}.2=3$

$x.\left(\dfrac{1}{2}+\dfrac{3}{5}\right)-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}=3+\dfrac{6}{5}$

$x.\dfrac{11}{10}=\dfrac{21}{5}$

$x=\dfrac{21}{5}:\dfrac{11}{10}$

$x=\dfrac{42}{11}$Câu trả lời: $\dfrac{1}{2}x+\dfrac{3}{5}\left(x-2\right)=3$

$\dfrac{1}{2}x+\dfrac{3}{5}.x-\dfrac{3}{5}.2=3$

$x.\left(\dfrac{1}{2}+\dfrac{3}{5}\right)-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}=3+\dfrac{6}{5}$

$x.\dfrac{11}{10}=\dfrac{21}{5}$

$x=\dfrac{21}{5}:\dfrac{11}{10}$

$x=\dfrac{42}{11}$

Hải Đăng · Answer

$\dfrac{1}{2}.x+\dfrac{3}{5}.\left(x-2\right)=3$

$\dfrac{1}{2}.x+\dfrac{3}{5}.x-\dfrac{3}{5}.2=3$

$x.\left(\dfrac{1}{2}+\dfrac{3}{5}\right)-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}=3+\dfrac{6}{5}$

$x.\dfrac{11}{10}=\dfrac{21}{5}$

$x=\dfrac{21}{5}:\dfrac{11}{10}$

$x=\dfrac{42}{11}$Câu trả lời: $\dfrac{1}{2}.x+\dfrac{3}{5}.\left(x-2\right)=3$

$\dfrac{1}{2}.x+\dfrac{3}{5}.x-\dfrac{3}{5}.2=3$

$x.\left(\dfrac{1}{2}+\dfrac{3}{5}\right)-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}-\dfrac{6}{5}=3$

$x.\dfrac{11}{10}=3+\dfrac{6}{5}$

$x.\dfrac{11}{10}=\dfrac{21}{5}$

$x=\dfrac{21}{5}:\dfrac{11}{10}$

$x=\dfrac{42}{11}$

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