\(\frac{-1275}{100}-2,75:\left(\frac{-11}{4}.x+11\right)=\frac{-27}{2}\)
\(2,75:\left(\frac{-11}{4}.x+11\right)=\frac{-1275}{100}-\frac{-27}{2}\)
\(2,75:\left(\frac{-11}{4}.x+11\right)=\frac{-51}{4}-\frac{-54}{4}\)
\(2,75:\left(\frac{-11}{4}.x+11\right)=\frac{3}{4}\)
\(\frac{-11}{4}.x+11=2,75:\frac{3}{4}\)
\(\frac{-11}{4}.x+11=\frac{11}{4}:\frac{3}{4}\)
\(\frac{-11}{4}.x+11=\frac{11}{4}.\frac{4}{3}\)
\(\frac{-11}{4}.x+11=\frac{11}{3}\)
\(\frac{-11}{4}.x=\frac{11}{3}-11\)
\(\frac{-11}{4}.x=\frac{11}{3}-\frac{33}{3}\)
\(\frac{-11}{4}.x=\frac{-22}{3}\)
\(x=\frac{-22}{3}:\frac{-11}{4}\)
\(x=\frac{-22}{3}.\frac{4}{-11}\)
\(x=\frac{8}{3}\)
Vậy \(x=\frac{8}{3}\)
