\(5\left(x-3\right)=2x+4\)
\(\Leftrightarrow5x-15=2x+4\)
\(\Leftrightarrow3x=19\)
\(\Leftrightarrow x=\dfrac{19}{3}.\)
Vậy ..........
5 . ( x-3 ) = 2x + 4
=> 5x - 15 = 2x + 4
=> 5x - 2x = 15 + 4
=> x3 = 19
=> x = \(\dfrac{19}{3}\)
\(5.(x-3)=2x+4\)
\(5x-15=2x+4\)
\(5x-15-4=2x\)
\(5x-19=2x\)
\(\Leftrightarrow\)\(5x-2x=19\)
\(3x=19\)
\(x=19:3\)
\(\dfrac{19}{3}\)
\(5\left(x-3\right)=2x+4\)
\(5x-15=2x+4\)
\(5x-2x=15+4\)
\(3x=19\)
\(x=\dfrac{19}{3}\)
Vậy \(x=\dfrac{19}{3}\).
