a, -(-a+c-d)-(c-a+d)
= a-c+d-c+a-d
= (a+a)+(-c-c)+(d-d)
= 2a-2c
b, -(a+b-c+d)+(a-b-c-d)
= -a-b+c-d+a-b-c-d
= (-a+a)+(c-c)+(-b-b)+(-d-d)
= -2b-2d
c, (a+b)(c+d)-(a+d)(b+c)
= (a+b)c+(a+b)d-(a+d)b-(a+d)c
= ac+bc+ad+bd-ab-bd-ac-cd
= (ac-ac)+(bd-bd)+(bc-ab)+(ad-cd)
= b(c-a)+d(a-c)
= b(c-a)-d(c-a)
= (b-d)(c-a)
d, a(b-c-d)-a(b+c-d)
= a[(b-c-d)-(b+c-d)]
= a[b-c-d-b-c+d]
= a[(b-b)+(-c-c)+(-d+d)]
= -2ca
Chúc bạn học tốt.....