`(2,4 .1/7 + 80% . 4/7 + 20%) . 20% + 3/5`
Đặt `A = (2,4 .1/7 + 80% . 4/7 + 20%) . 20% + 3/5`
`A = (12/5 . 1/7 + 80% . 4/7 + 20%) . 20% + 3/5`
`A = (12/35 + 16/35 + 1/5) . 20% + 3/5`
`A = (12/35 + 16/35 + 7/35) . 20% + 3/5`
`A` \(=\left(\dfrac{12+16+7}{35}\right).20\%+\dfrac{3}{5}\)
`A = 35/35 . 20% + 3/5`
`A = 1.20% + 3/5`
`A=20% + 3/5`
`A= 1/5+3/5`
`A=4/5`
Vậy `75%` của `A` là :
`4/5 xx 75% = 3/5`
Vậy...
`#LeMichael`
