b: \(\frac27=\frac{2\times40}{7\times40}=\frac{80}{280}\)
\(\frac45=\frac{4\times56}{5\times56}=\frac{224}{280}\)
\(\frac58=\frac{5\times35}{8\times35}=\frac{175}{280}\)
mà 80<175<224
nên \(\frac27<\frac58<\frac45\) <1(1)
Ta có: \(1=\frac66;1=\frac22<\frac32\)
=>\(1=\frac66<\frac32\) (2)
Từ (1),(2) suy ra \(\frac27<\frac58<\frac45<\frac66<\frac32\)
a: \(\frac43=\frac{4\times28}{3\times28}=\frac{112}{84};\frac76=\frac{7\times14}{6\times14}=\frac{98}{84}\)
\(\frac14=\frac{1\times21}{4\times21}=\frac{21}{84};\frac17=\frac{1\times12}{7\times12}=\frac{12}{84}\)
mà 12<21<98<112
nên \(\frac17<\frac14<\frac76<\frac43\)

