Câu trả lời:
\(A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+....+\frac{2}{37.39}\)
\(=\frac{1}{3}-\frac{1}{39}\)
\(=\frac{12}{39}\)
\(B=\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+....+\frac{3}{73.76}\)'
\(=\frac{1}{4}-\frac{1}{76}\)
\(=\frac{9}{38}\)