A= \(\left(\frac{2\sqrt{x}+x}{x\sqrt{x}-1}-\frac{1}{\sqrt{x}-1}\right):\frac{\sqrt{x}+2}{x+\sqrt{x}+1}\left(x\ge0;x\ne1\right)\)

B=\(\frac{1}{\sqrt{x}+1}\)

Với M=A:B so sánh M² và \(\sqrt{M}\)

A=\(\left(\frac{1}{\sqrt{a}-1}-\frac{2\sqrt{a}}{a\sqrt{a}+\sqrt{a}-a-1}\right):\frac{\sqrt{a}-2}{a+1}\left(a\ge0;a\ne1\right)\)

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