Question

\(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}\)

Answer 1

\(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}=\dfrac{3}{6}-\dfrac{4}{6}+\dfrac{3}{4}=\dfrac{-1}{6}+\dfrac{3}{4}=\dfrac{-4}{24}+\dfrac{18}{24}=\dfrac{14}{24}=\dfrac{7}{12}\)