\(3+\dfrac{9}{4}\times\dfrac{5}{3}=3+\dfrac{3}{4}\times5=3+\dfrac{15}{4}=\dfrac{36}{12}+\dfrac{45}{12}=\dfrac{81}{12}=\dfrac{27}{4}\)
\(3+\dfrac{9}{4}:\dfrac{3}{5}\\ =\dfrac{36}{12}+\dfrac{9}{4}\times\dfrac{5}{3}\\ =\dfrac{36}{12}+\dfrac{45}{12}\\ =\dfrac{81}{12}=\dfrac{27}{4}\)
= 3 + 9/4 x 5/3
= 3 + 9 x 5/4 x 3
= 3 + 45/12
= 3/1 + 45/12
= 36/12 + 45/12
= 81/12
\(3+\dfrac{9}{4}\div\dfrac{3}{5}=3+\dfrac{3}{4}\times5=3+\dfrac{15}{4}=\dfrac{36}{12}+\dfrac{45}{12}=\dfrac{27}{4}\)