a)\(\dfrac{9}{12}=\dfrac{9:3}{12:3}=\dfrac{3}{4}\)
Vì 2x4<3x3
=>\(\dfrac{2}{3}< \dfrac{3}{4}\)
b)\(\dfrac{4}{8}=\dfrac{4:4}{8:4}=\dfrac{1}{2}\)
Vì 1x3<2x2
=>\(\dfrac{1}{2}< \dfrac{2}{3}\)
a) \(\dfrac{9}{12}\)=\(\dfrac{3}{4}\)
\(\dfrac{2}{3}=\dfrac{2.4}{3.4}\)=\(\dfrac{8}{12}\)
\(\dfrac{3}{4}=\dfrac{3.3}{4.3}=\dfrac{9}{12}\)
Vì \(\dfrac{9}{12}>\dfrac{8}{12}=>\)\(\dfrac{9}{12}>\dfrac{3}{4}\)
b) \(\dfrac{4}{8}=\dfrac{2}{4}\)
Ta có: \(\dfrac{2}{3}>\dfrac{2}{4}=>\dfrac{4}{8}< \dfrac{2}{3}\)
a)\(\dfrac{9}{12}=\dfrac{3}{4}\)
\(\dfrac{2}{3}=\dfrac{2\times4}{3\times4}=\dfrac{8}{12}\)
\(\Rightarrow\dfrac{8}{12}< \dfrac{9}{12}\) hay \(\dfrac{2}{3}< \dfrac{3}{4}\)
b)\(\dfrac{4}{8}=\dfrac{1}{2}\)
\(\dfrac{1}{2}=\dfrac{1\times3}{2\times3}=\dfrac{3}{6}\)
\(\dfrac{2}{3}=\dfrac{2\times2}{3\times2}=\dfrac{4}{6}\)
\(\Rightarrow\dfrac{3}{6}< \dfrac{4}{6}\) hay \(\dfrac{1}{2}< \dfrac{2}{3}\)
