Tính \(\lim\limits_{x\rightarrow0}\dfrac{\sqrt{1+2x}-1}{2x}\) .
\(1\).\(2\).\(\dfrac{1}{2}\).\(0\).Hướng dẫn giải:\(\lim\limits_{x\rightarrow0}\frac{\sqrt{1+2x}-1}{2x}=\lim\limits_{x\rightarrow0}\frac{2x}{2x\left(\sqrt{1+2x}+1\right)}=\lim\limits_{x\rightarrow0}\frac{1}{\sqrt{1+2x}+1}=\frac{1}{2}\)