Tìm x thỏa mãn \(\dfrac{1}{2}.x+\dfrac{3}{4}=\dfrac{-1}{4}\).
-2.-4.\(\dfrac{1}{2}.\)\(\dfrac{-1}{2}.\).Hướng dẫn giải:\(\dfrac{1}{2}.x+\dfrac{3}{4}=\dfrac{-1}{4}\\ \dfrac{1}{2}.x=\dfrac{-1}{4}-\dfrac{3}{4}\\ \dfrac{1}{2}.x=-1\\ x=-1:\dfrac{1}{2}\\ x=-2.\)
