Tích phân \(\int\limits^{\pi}_0\cos^2x.\sin x\text{d}x\) bằng
\(-\frac{2}{3}\). \(\frac{2}{3}\). \(\frac{3}{2}\). \(0\). Hướng dẫn giải:\(\int\limits^{\pi}_0\cos^2x.\sin x\text{d}x=-\int\limits^{\pi}_0\cos^2x\text{d}\left(\cos x\right)\) \(=-\frac{\cos^3x}{3}|^{\pi}_0=\frac{2}{3}\).