\(\sqrt{3}+\sqrt{12}+\sqrt{48}\) = ?
\(7\sqrt{3}\). \(7+\sqrt{3}\). \(6\sqrt{3}\). \(3\sqrt{7}\). Hướng dẫn giải:\(\sqrt{3}+\sqrt{12}+\sqrt{48}\)\(=\sqrt{3}+\sqrt{4.3}+\sqrt{16.3}=\sqrt{3}+2\sqrt{3}+4\sqrt{3}=\)\(=\sqrt{3}\left(1+2+4\right)=7\sqrt{3}\)