Giải hệ phương trình \(\left\{{}\begin{matrix}x+3y+2z=8\\2x+2y+z=6\\3x+y+z=6\end{matrix}\right.\) ta được nghiệm là
\(\left(x;y;z\right)=\left(1;1;2\right)\).\(\left(x;y;z\right)=\left(1;2;1\right)\).\(\left(x;y;z\right)=\left(-1;1;-2\right)\).\(\left(x;y;z\right)=\left(-1;-1;-2\right)\).