Giá trị của biểu thức \(A=\dfrac{2^7.9^3}{6^5.8^2}\) là
\(\dfrac{9}{16}.\)\(\dfrac{3}{2}.\)\(\dfrac{3}{16}.\)\(\dfrac{9}{4}.\)Hướng dẫn giải:\(A=\dfrac{2^7.9^3}{6^5.8^2}=\dfrac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\dfrac{2^7.3^6}{2^5.3^5.2^6}=\dfrac{2^7.3^6}{2^{11}.3^5}=\dfrac{2^7.3^5.3}{2^7.2^4.3^5}=\dfrac{3}{2^4}=\dfrac{3}{16}.\)