Giá trị biểu thức \(\dfrac{3}{2}\sqrt{6}+2\sqrt{\dfrac{2}{3}}-4\sqrt{\dfrac{3}{2}}\) là
\(\dfrac{\sqrt{6}}{6}\)\(\sqrt{6}\)\(\dfrac{\sqrt{6}}{2}\)\(\dfrac{\sqrt{6}}{3}\)Hướng dẫn giải:\(\dfrac{3}{2}\sqrt{6}+2\sqrt{\dfrac{2}{3}}-4\sqrt{\dfrac{3}{2}}=\dfrac{3}{2}\sqrt{6}+\dfrac{2\sqrt{6}}{3}-\dfrac{4\sqrt{6}}{2}=\sqrt{6}\left(\dfrac{3}{2}+\dfrac{2}{3}-\dfrac{4}{2}\right)=\dfrac{\sqrt{6}}{6}\)