Tích phân \(\int\limits^{\pi}_0\cos^3x.\sin x\text{d}x\) bằng
\(-\dfrac{1}{4}\pi^4\).\(-\pi^4\).\(0\).\(-\dfrac{1}{4}\).Hướng dẫn giải:\(\int\limits^{\pi}_0\cos^3x.\sin x\text{d}x=-\int\limits^{\pi}_0\cos^3x\text{d}\left(\cos x\right)=-\dfrac{1}{4}\cos^4x|^{\pi}_0=-\dfrac{1}{4}\left(\cos^4\pi-\cos^40\right)=0\).