Đặt A là tên biểu thức

A=1.2.3+2.3.4+...+n(n+1)(n+2)

4A=1.2.3.4+2.3.4.4+...+n(n+1)(n+2).4

4A=1.2.3.4 - 0.1.2.3 + 2.3.4.5 - 1.2.3.4 +...+ n(n+1)(n+2)(n+3) - (n-1)n(n+1)(n+2)

4A=[1.2.3.4+2.3.4.5+...+n(n+1)(n+2)(n+3)] - [0.1.2.3+1.2.3.4+...+(n-1)n(n+1)(n+2)]

4A=n(n+1)(n+2)(n+3)-0.1.2.3

A=\(\frac{n\left(n+1\right)\left(n+2\right)\left(n+3\right)}{4}\)

\(A=1.2.3+2.3.4+3.4.5+...+n\left(n+1\right)\left(n+2\right)\)

\(\Rightarrow4A=1.2.3.4+2.3.4.4+3.4.5.4+...+4n\left(n+1\right)\left(n+2\right)\)

\(\Rightarrow4A=1.2.3.4+1.2.3.\left(5-1\right)+...+n\left(n+1\right)\left(n+2\right)\left(n+3-n+1\right)\)

\(\Rightarrow4A=1.2.3.4+2.3.4.5-1.2.3.4+...+n\left(n+1\right)\left(n+2\right)\left(n+3\right)-\left(n-1\right)n\left(n+1\right)\left(n\right)\)

\(\Rightarrow4A=n\left(n+1\right)\left(n+2\right)\left(n+3\right)\)

\(\Rightarrow A=\frac{n\left(n+1\right)\left(n+2\right)\left(n+3\right)}{4}\)

=1-1/2+1/2-1/3+1/3-1/4+.....+1/n-1/n+1

=1-1/n+1

=n/n+1

Ta có : 1/ 1.2 + 1/ 2.3 + 1/ 3.4 + ... + 1/ n.( n + 1 ) .

= 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ..... + 1/n - 1/ n+1 .

= 1 - 1/ n + 1 .

= n+1 / n+1 - 1/ n+1 .

= n/ n+1 .

Đáp sô : n/ n+1

hộ mình cái nha

Ta có :
Gọi A=1.2+2.3+3.4+4.5+...+49.50
 A=1.2+2.3+3.4+4.5+...+49.50
 3.A=3.(1.2+2.3+3.4+4.5+...+49.50)
 3.A=1.2.3+2.3.3+3.3.4+3.4.5+...+3.49.50
 3.A=1.2.(3-0)+2.3.(3-0)+(3-0).3.4+(3-0).4.5+...+(3-0).49.50
 3.A=1.2.3-0+2.3.3-0+3.3.4-0+3.4.5-0+...+3.49.50-0
 3.A=1.2.3-0+2.3.4-1.2.3+5.3.4-2.3.4+...+49.50.51-48.49.50
 3.A=49.50.51
 A=\(\frac{49.50.51}{3}\)49.50.513
 A=\(\frac{49.50.17.3}{3}\)49.50.17.33
 A=49.50.17
 A=41650
Đáp số : A=41650

3S=1.2.3+2.3.(4-1)+3.4.(5-2)+...+49.50.(51-48)

=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-...-48.49.50+49.50.51

=49.50.51

=124950

3S=1.2.3+2.3.3+3.4.3+...+49.50.3

=1.2.3+2.3.(4-1)+3.4.(5-2)+...+48.49.(50-47)+49.50.(51-48)

=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+48.49.50-47.48.49+49.50.51-48.49.50

=(1.2.3-1.2.3)+(2.3.4-2.3.4)+...(47.48.49-47.48.49)-(48.49.50-48.49.50)+49.50.51

=0+0+...+0+0+49.50.51

=49.50.51

S=(49.50.51)/3

=41650

Đáp số:41650

\(A=\frac{9}{1.2}+\frac{9}{2.3}+\frac{9}{3.4}+...+\frac{9}{98.99}+\frac{9}{99.100}\)

\(A=\frac{1}{9}.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)

\(A=\frac{1}{9}.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)

\(A=\frac{1}{9}.\left(1-\frac{1}{100}\right)\)

\(A=\frac{1}{9}.\frac{99}{100}\)

\(A=\frac{11}{100}\)

A = 9/1.2 + 9/2.3 + 9/3.4 +...+ 9/98.99 + 9/99.100

   = 9. (1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/98 - 1/99 + 1/99 - 1/100)

   = 9. (1 - 1/100)

   = 9 . 99/100

   = 891/100

=9.(1/1.2+1/2.3+1/3.4+...+1/98.99+1/99.100)

=9.(1/1-1/2+1/2-1/3+1/3-1/4+....+1/98-1/99+1/99-1/100)

=9.(1/1-1/100)

=9-9/100

=891/100

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{200.201}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{200}-\frac{1}{201}\)

\(=1-\frac{1}{201}\)

\(=\frac{200}{201}\)

 \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{200.201}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{200}-\frac{1}{201}\)

\(=1-\frac{1}{201}=\frac{200}{201}\)

Ủng hộ nha,tớ ko ăn cóp đâu.

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{200.201}\)

\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{200}-\frac{1}{201}\)

\(=\frac{1}{1}-\frac{1}{201}\)

\(=\frac{200}{201}\)

100 số hạng đầu là

\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{100.101}\)

ta có \(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{100.101}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{100}-\frac{1}{101}=1-\frac{1}{101}\)\(=\frac{100}{101}\)

2:

A=-(1/4-1/5+1/5-1/6+...+1/9-1/10)

=-(1/4-1/10)

=-1/4+1/10

=-5/20+2/20=-3/20