2 ) 1.2 + 2.3 + 3.4 + ... + x.( x + 1 ) = 5850

Đặt A = 1.2 + 2.3 + 3.4 + ... + x.( x + 1 )

=> 3A = 1.2.3 + 2.3.( 4 - 1 ) + 3.4.(5 - 2 ) + ... + x.( x + 1 ). [ ( x + 2 ) - ( x - 1 ) ] 

= 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + x . ( x + 1 ) . ( x + 2 ) - ( x - 1 ). x . ( x + 1 )

= x . ( x + 1 ) . ( x + 2 )

=> A = [ x . ( x + 1 ) . ( x + 2 ) ] : 3

Mà tổng A = 5850

=> [ x . ( x + 1 ) . ( x + 2 ) ] : 3 = 5850

=> x . ( x + 1 ) . ( x + 2 ) = 17550

x . ( x + 1 ) . ( x + 2 ) = 25 . 26 . 27 

=> x = 25

Vậy x = 25

Bài 2: 

a: \(3x^2-3xy=3x\left(x-y\right)\)

b: \(x^2-4y^2=\left(x-2y\right)\left(x+2y\right)\)

c: \(3x-3y+xy-y^2=\left(x-y\right)\left(3+y\right)\)

d: \(x^2-y^2+2y-1=\left(x-y+1\right)\left(x+y-1\right)\)

ỳtct7ct7c7c7t79tc9

Giải:

Bài 1:

a) \(6^2\): 4 . 3 + 2 . \(5^2\) 

= 36 : 4 . 3 + 2 . 25

= 27 + 50

= 77

77 = 7 . 11

b) 5 . \(4^2\) - 18 : \(3^2\)

= 5 . 16 - 18 : 9

= 80 - 2

= 78

78 = 2 .3 . 13

Bài 2: 

a) Ta có: \(70⋮x\)

\(84⋮x\)

Do đó: \(x\inƯC\left(70;84\right)\)

\(\Leftrightarrow x\inƯ\left(14\right)\)

\(\Leftrightarrow x\in\left\{1;2;7;14\right\}\)

mà x>8

nên x=14

2:

a: \(=\left(2x^2-xy\right)+\left(2xz-yz\right)\)

\(=x\left(2x-y\right)+z\left(x-2y\right)=\left(x-2y\right)\left(x+z\right)\)

b: \(=\left(x^2-4y^2\right)-\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x+2y\right)-\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x+2y-1\right)\)

c: \(=\left(y^2+10y+25\right)-9z^2\)

\(=\left(y+5\right)^2-\left(3z\right)^2\)

\(=\left(y+5+3z\right)\left(y+5-3z\right)\)

d: \(=\left(x+2y\right)^3-\left(x-2y\right)\left(x+2y\right)\)

\(=\left(x+2y\right)\left[\left(x+2y\right)^2-\left(x-2y\right)\right]\)

\(=\left(x+2y\right)\left(x^2+4xy+4y^2-x+2y\right)\)

1:

a: \(x\left(3-4x\right)+5\left(3-4x\right)=\left(3-4x\right)\left(x+5\right)\)

b: \(2y\left(5y-6\right)-4\left(6-5y\right)\)

\(=2y\left(5y-6\right)+4\left(5y-6\right)\)

\(=2\left(5y-6\right)\left(y+2\right)\)

c: \(=27\left(x-2\right)^3-3x\left(x-2\right)^2\)

\(=3\left(x-2\right)^2\cdot\left[9\left(x-2\right)-x\right]\)

\(=3\left(x-2\right)^2\left(8x-18\right)=6\left(x-2\right)^2\cdot\left(4x-9\right)\)

d: \(=6y\left(x-y\right)\left(x+y\right)-8y\left(x+y\right)^2\)

\(=2y\left(x+y\right)\left[3\left(x-y\right)-4\left(x+y\right)\right]\)

\(=2y\left(x+y\right)\left(3x-3y-4x-4y\right)\)

\(=2y\left(x+y\right)\left(-x-7y\right)\)

Bài 1

a) x(3 - 4x) + 5(3 - 4x)

= (3 - 4x)(x + 5)

b) 2y(5y - 6) - 4(6- 5y)

= 2y(5y - 6) + 4(5y - 6)

= (5y - 6)(2y + 4)

= 2(5y - 6)(y + 2)

c) 27(x - 2)³ - 3x(2 - x)²

= 27(x - 2)³ - 3x(x - 2)²

= 3(x - 2)²[9(x - 2) - x]

= 3(x - 2)²(9x - 18 - x)

= 3(x - 2)²(8x - 18)

= 6(x - 2)²(4x - 9)

d) 6y(x² - y²) - 8y(x + y)²

= 6y(x - y)(x + y) - 8y(x + y)²

= 2y(x + y)[3(x - y) - 4(x + y)]

= 2y(x + y)(3x - 3y - 4x - 4y)

= 2y(x + y)(-x - 7y)

= -2y(x + y)(x + 7y)

A) 5.(x-4)=123-38

5.(x-4)=85

x-4=85:5

x-4=17

x=17+4

x=21 

câu b tương tự

2)(x:3-4) . 5=15

=> x:3-4=15:5

=> x:3-4=3

=> x:3=3+4

=> x:3=7

=> x=7.3

=> x=21

b3 tự làm

b4a) Vì 70 chia hết x;84 chia hết x => x ∈ ƯC(70,84)

ƯCLN(70,84)=14                 ƯC(70,84)=Ư(14)={1,2,7,14}

Vì x>8 =>x=14

b) Vì x chia hết cho12; x chia hết cho 25; x chia hết cho 30=> x ∈ BC(12,25,30)

BCNN(12,25,30)=300                    BC(12,25,30)=B(300)={0;300;600;....}

Vì 0 x=300

Bài 1

a) 123-5(x+4)=38                                    b)(3x-2⁴).7³=2.7³

         5(x+4)=123-38                                 (3x-16)    =2.7³:7³

         5(x-4)=85                                        (3x-16)   =2.1

           (x-4)=85:5                                      3x         =2+16

          (x-4)=17                                         3x          =18

           x    =17+4                                       x          =18-3

          x     =21                                          x           =15

Vậy x=21                                                Vậy x=15

Bài 2

Theo đề bài ta có

(x:3-4).5=15

x:3-4    =15:5

x:3-4    =3

x:3       =3+4

x:3      =7

x          =7.3

x          =21

Vậy x=21

Bài 3

a) 6²:4.3+2.5²                              b) 5.4²-18:3²

=36:4.3+2.25                               = 5.16-18:9

=9.3+50                                     = 90-2

=27+50                                      = 82

=107

Phân tích ra thừa số nguyên tố

107=1.107( vì 107 là số nguyên tố)

82=2.41

Bài 4

a) \(70⋮x,84⋮x=>x\varepsilonƯC\left(70,84\right)\) (x>8)

Tìm ƯCLN(70, 84)

70=2.5.7

84=2².3.7

=> ƯCLN(70, 84)= 2.7=14

=> x\(\varepsilon\){1,2,7,14}

Vì x>8 nên

x=14

b) \(x⋮12,x⋮25=>x\varepsilon BC\left(12,25\right)\) (0<x<500)

Tìm BCNN(12,25)

12=2².3

25=5²

\(=>BCNN\left(12,25\right)=2^2.3.5^2=300\)

=> x\(\varepsilon\){0, 300, 600,.....}
Vì 0<x<500 nên

x=300

Bài này làm lâu lắm nhớ k mik đấy

bài 1:

a) x(x-2)-5y-(x-2)=(x-5y)(x-2)

b) =(2x-3-4x)(2x-3+4x)=(-2x-3)(6x-3)

bài 2 bạn tự luyện nhé

\(a,2x\left(x^3-3\right)-2x^4=18\\ 2x^4-6x-2x^4=18\\ -6x=18\\ x=-3\)

\(b,9x\left(4-x\right)+\left(3x+1\right)^2=2\\ 36x-9x^2+9x^2+6x+1=2\\ 42x=2-1\\ 42x=1\\ x=\dfrac{1}{42}\)

\(a,\Leftrightarrow2x^4-3x-2x^4=18\Leftrightarrow-3x=18\Leftrightarrow x=-6\\ b,\Leftrightarrow36x-9x^2+9x^2+6x+1=2\\ \Leftrightarrow42x=1\Leftrightarrow x=\dfrac{1}{42}\)

Bài 1:

\(a,=11\left(x+y\right)+x\left(x+y\right)=\left(x+11\right)\left(x+y\right)\\ b,=225-\left(2x+y\right)^2=\left(15-2x-y\right)\left(15+2x+y\right)\)

Bài 2:

\(A=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\\ A=\left(72-2\right)\left(120-2\right)=70\cdot118=8260\)

Bài 3:

\(a,\Leftrightarrow\left(x+1\right)^2-\left(x+1\right)=0\\ \Leftrightarrow\left(x+1\right)\left(x+1-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\\ b,\Leftrightarrow x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=49\\ \Leftrightarrow24x+25=49\\ \Leftrightarrow24x=24\Leftrightarrow x=1\)

thk you very much UwU

2:

a: \(9x^2-1=\left(3x\right)^2-1=\left(3x-1\right)\left(3x+1\right)\)

b: \(2\left(x-1\right)+x^2-x\)

\(=2\left(x-1\right)+x\left(x-1\right)\)

\(=\left(x-1\right)\left(x+2\right)\)

c: \(3x^2+14x-5\)

\(=3x^2+15x-x-5\)

\(=3x\left(x+5\right)-\left(x+5\right)=\left(x+5\right)\left(3x-1\right)\)

3: 

a: \(2x\left(x-1\right)-2x^2=4\)

=>\(2x^2-2x-2x^2=4\)

=>-2x=4

=>x=-2

b: \(x\left(x-3\right)-\left(x+2\right)\left(x-1\right)=5\)

=>\(x^2-3x-\left(x^2+x-2\right)=5\)

=>\(x^2-3x-x^2-x+2=5\)

=>-4x=3

=>x=-3/4

c: \(4x^2-25+\left(2x+5\right)^2=0\)

=>\(\left(2x-5\right)\left(2x+5\right)+\left(2x+5\right)^2=0\)

=>\(\left(2x+5\right)\left(2x-5+2x+5\right)=0\)

=>4x(2x+5)=0

=>\(\left[{}\begin{matrix}x=0\\x=-\dfrac{5}{2}\end{matrix}\right.\)