11 x 11 = 121 , 11 x 12 = 132 , 11 x 13 = 143
Hỏi 11 x 19 = ?
d) 12 x 156 - 12 x 55 - 12
e) 12 x 11 + 21 x 11 + 11 x 33
g) 132 x 11 - 11 x 32 - 54 x 11
d) 12x 156 - 12 x 55 - 12
= 12 x ( 156 - 55 - 12 )
= 12 x 100
= 1200
e ) 12 x 11 + 21 x 11 + 11 x 33
= ( 12+ 21 + 33) x 12
= 66 x 11
= 726
g) 132 x 11 - 11 x 32 - 54 x 11
= ( 132 - 32 - 54 ) x 11
= 46 x 11
= 506
d) 12 x 156 - 12 x 55 - 12 = 12x(156 - 55 - 1 ) = 12 x 100 = 1200
e) 12 x 11 + 21 x 11 + 11 x 33 = 11 x ( 12 + 21 + 33 ) = 11 x 66 = 726
g) 132 x 11 - 11 x 32 - 54 x 11 = 11 x ( 132 - 32 - 54 ) = 11 x 46 = 506
d) \(12\times156-12\times55-12\) \(=12\times\left(156-55-1\right)\)
\(=12\times100=1200\)
e) \(12\times11+21\times11+11\times33\)\(=11\times\left(12+21+33\right)=11\times66=726\)
g) \(132\times11-11\times32-54\times11\) \(=11\times\left(132-32-54\right)=11\times46=506\)
13/19 x23/11 -13/19 x 8/11 - 13/19 x 4/11
13/19x23/11-13/19x8/11-13/19x4/11
=(23/11-8/11-4/11)=11/11=1
=13/19x1
=13/19
tính bằng cách thuận tiện nhất :
a, 13/19 x 23/11 - 13/19 x 8/11 - 13/ 19 x 4/11
13/19 x 23/11 - 13/19 x 8/11 - 13/19 x 4/11
= 13/19 x (23/11 - 8/11 - 4/11)
= 13/19 x 1
= 13/19
\(\dfrac{13}{19}\times\dfrac{23}{11}-\dfrac{13}{19}\times\dfrac{8}{11}-\dfrac{13}{19}\times\dfrac{4}{11}\\ =\dfrac{13}{19}\times\left(\dfrac{23}{11}-\dfrac{8}{11}-\dfrac{4}{11}\right)\\ =\dfrac{13}{19}\times1=\dfrac{13}{19}\)
câu b, 20/5x7 + 20/7x9 + 20/ 9 x11 + ..... 20 / 33 x35
Tính giá trị của các biểu thức sau bằng cách thuận tiện
a) 12 x 11 + 21 x 11 + 11 x 33
b) 132 x 11 – 11 x 32 – 54 x 11
c) 245 x 11 + 11 x 365
d) 78 x 75 + 75 x 89 + 75 x 123
e) 2 x 250 x 50 x 8
g) 1994 x 867 + 1994 x 11
a)12 x 11 + 21 x 11 x 11 + 11 x 33
= ( 12 x 11 ) + ( 21 x 11 x 11 ) + ( 11 x 33 )
= 132+2541+363132+2541+363
= 30363036
b)132x11-11x32-54x11
= ( 132 x 11 ) - ( 11 x 32 ) - ( 54 x 11 )
=1452−352−594=1452−352−594
= 506506
\(a,=11\times\left(12+21+33\right)=11\times66=726\\ b,=11\times\left(132-32-54\right)=11\times46=506\\ c,=11\times\left(245+365\right)=11\times610=6710\\ d,=75\times\left(78+89+123\right)=75\times290=21750\\ e,=\left(2\times50\right)\times\left(250\times8\right)=100\times2000=200000\\ g,=1994\times\left(867+11\right)=1994\times878=1750732\)
a) 12 x 11 + 21 x 11 + 11 x 33
= 11 x ( 12 + 21 + 33)
= 11 x 66
= 726
b) 132 x 11 - 11 x 32 - 54 x 11
= 11 x ( 132 - 32 - 54)
= 11 x 46
= 506
c) 245 x 11 + 11 x 365
= 11 x ( 245 + 365 )
= 11 x 610 = 6710
d) 78 x 75 + 75 x 89 + 75 x 123
= 75 x ( 78 + 89 + 123)
= 75 x 290 = 21750
e) 2 x 250 x 50 x 8
= (2 x 50) x ( 250 x 8)
= 100 x 2000 = 200000
g) 1994 x 867 + 1994 x 11
= 1994 x ( 867 + 11)
= 1994 x 878 = 1750732
tính bằng cách thuận tiện nhất
a,4/15 x 7/8 + 4/15 x 2/9
b, 13/29 x 23/11 -13/19 x 8/11 - 13/19 x 4/11
x=(-11)+(-12)+(-13)+...+(-19)
(x+2/)10^10)+(x+2)/11^11)=(x+2)/12^12)+(x+2)/13^13)
\(\Rightarrow\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}-\frac{x+2}{12^{12}}-\frac{x+2}{13^{13}}=0\)
\(\Rightarrow\left(x+2\right)\left(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\right)=0\)
Vì \(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\ne0\)
=>x+2=0
=>x=-2
Vậy x=-2
Tìm x biết : x+2/10^10+x+2/11^11=x+2/12^12+x+2/13^13
tim x biet (x+2)/10^10+(x+2)/11^11=(x+2)/12^12+(x+2)/13^13
=>
\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}-\frac{x+2}{12^{12}}-\frac{x+2}{13^{13}}=0\)
=>\(\left(x+2\right).\left(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}=0\right)\)
vì \(\frac{1}{10^{10}}>\frac{1}{11^{11}}>\frac{1}{12^{12}}>\frac{1}{13^{13}}=>\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\ne0\)
=>x+2=0
=>x=-2
tick nhé
\(\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}=\frac{x+2}{12^{12}}+\frac{x+2}{13^{13}}\)
\(=>\frac{x+2}{10^{10}}+\frac{x+2}{11^{11}}-\frac{x+2}{12^{12}}-\frac{x+2}{13^{13}}=0\)
\(=>\left(x+2\right).\left(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\right)=0\)
Vì \(\frac{1}{10^{10}}>\frac{1}{11^{11}}>\frac{1}{12^{12}}>\frac{1}{13^{13}}\)
Nên \(\frac{1}{10^{10}}+\frac{1}{11^{11}}-\frac{1}{12^{12}}-\frac{1}{13^{13}}\)khác 0
Suy ra: x+2=0
x =0 - 2
x = -2
TICK NHA