* \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\Leftrightarrow24x^2-10x-24x^2+8x=30\) \(\Leftrightarrow-10x+8x=30\Leftrightarrow-2x=30\Leftrightarrow x=\dfrac{30}{-2}=-15\) vậy \(x=-15\)

* \(3x\left(3-2x\right)+6x\left(x-1\right)=15\Leftrightarrow9x-6x^2+6x^2-6x=15\)

\(\Leftrightarrow9x-6x=15\Leftrightarrow3x=15\Leftrightarrow x=\dfrac{15}{3}=5\) vậy \(x=5\)

a, \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(24x^2-10x-24x^2+8x=30\)

\(\left(24x^2-24x^2\right)-\left(10x-8x\right)=24\)

\(-2x=24\)

\(x=-12\)

b, \(3x\left(3-2x\right)+6x\left(x-1\right)=15\)

\(9x-6x^2+6x^2-6x=15\)

\(\left(9x-6x\right)+\left(-6x^2+6x^2\right)=15\)

\(3x=15\)

\(x=5\)

Câu a : \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(\Leftrightarrow24x^2-10x-24x^2+8x=30\)

\(\Leftrightarrow-2x=30\)

\(\Leftrightarrow x=-15\)

Vậy \(x=-15\)

Câu b : \(3x\left(3-2x\right)+6x\left(x-1\right)=15\)

\(\Leftrightarrow9x-6x^2+6x^2-6x=15\)

\(\Leftrightarrow3x=15\)

\(\Leftrightarrow x=5\)

Vậy \(x=5\)

a, 2x(12x−5)−8x(3x−1)=302x(12x−5)−8x(3x−1)=30

24x2−10x−24x2+8x=3024x2−10x−24x2+8x=30

(24x2−24x2)−(10x−8x)=24(24x2−24x2)−(10x−8x)=24

−2x=24−2x=24

x=−12

b, 3x(3−2x)+6x(x−1)=153x(3−2x)+6x(x−1)=15

9x−6x2+6x2−6x=159x−6x2+6x2−6x=15

(9x−6x)+(−6x2+6x2)=15(9x−6x)+(−6x2+6x2)=15

3x=153x=15

x=5

* \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\Leftrightarrow24x^2-10x-24x^2+8x=30\) \(\Leftrightarrow-10x+8x=30\Leftrightarrow-2x=30\Leftrightarrow x=\dfrac{30}{-2}=-15\) vậy \(x=-15\)

* \(3x\left(3-2x\right)+6x\left(x-1\right)=15\Leftrightarrow9x-6x^2+6x^2-6x=15\)

\(\Leftrightarrow9x-6x=15\Leftrightarrow3x=15\Leftrightarrow x=\dfrac{15}{3}=5\) vậy \(x=5\)

\(a,2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(\Leftrightarrow24x^2-10x-24x^2+8x=30\)

\(\Leftrightarrow-2x=30\)

\(\Leftrightarrow x=-15\)

\(b,3x\left(3-2x\right)+6x\left(x-1\right)=15\)

\(\Leftrightarrow9x-6x^2+6x^2-6x=15\)

\(\Leftrightarrow3x=15\)

\(\Leftrightarrow x=-5\)

a) \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(\Leftrightarrow24x^2-10x-24x^2+8x=30\)

\(\Leftrightarrow-10x+8x=30\Leftrightarrow-2x=30\Leftrightarrow x=\dfrac{30}{-2}=-15\)

vậy \(x=-15\)

b) đề có sai o bn

a) đề = 24x^2-10x-24x^2+8x=30

= -10x+8x =30

\(\Rightarrow\)x=-15

b)đề \(\Leftrightarrow\)9x-6x^2=6x^2-6x=15

\(\Leftrightarrow\)9x-6x^2-6x^2+6x=15

\(\Leftrightarrow\)15x=15

\(\Rightarrow\)x=1

\(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(\Leftrightarrow24x^2-10x-24x^2+8x=30\)

\(\Leftrightarrow-2x=30\)

\(\Leftrightarrow x=-15\)

<br class="Apple-interchange-newline"><div></div>2x(12x−5)−8x(3x−1)=30

<=>\(24x^2-10x-24x^2+8x=30\)

<=>\(-2x=30\)

<=>\(x=30:\left(-2\right)\)

<=>\(x=-15\)

Bài làm :

\(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(\Leftrightarrow24x^2-10x-24x^2+8x=30\)

\(\Leftrightarrow-10x+8x=30\)

\(\Leftrightarrow-2x=30\)

\(\Leftrightarrow x=30:\left(-2\right)\)

\(\Leftrightarrow x=-15\)

Học tốt

1) 2x - 378 = 122

=> 2x = 122 + 378

=> 2x = 500

=> x = 500 : 2

=> x = 250

2) 8x - 4x = 1208

=> 4x = 1208

=> x = 1208 : 4

=> x = 302

3) x - 382 = 159 : 3

=> x - 382 = 53

=>  x = 53 + 382

=> x = 435

4) 3x + 30 = 420

=> 3x = 420 - 30

=> 3x = 390

=> x = 390 : 3

=> x = 130

5) 12x  - 13x - 500 = 1500

=> -x = 1500 + 500

=> -x = 2000

=> x = -2000

1,\(2x-378=122\)

\(2x=122+378\)

\(2x=500\)

\(x=500:2\)

\(x=250\)

2,\(8x-4x=1208\)

\(x.\left(8-4\right)=1208\)

\(x.4=1208\)

\(x=1208:4\)

\(x=302\)

3,\(x-382=159:3\)

\(x-382=53\)

\(x=52+382\)

\(x=434\)

4,\(3x+30=420\)

\(3x=420-30\)

\(3x=390\)

\(x=390:3\)

\(x=130\)

5,\(12x-13x-500=1500\)

như câu 2 

\(1,2x-378=122\)\(\Rightarrow2x=500\Rightarrow x=250\)

\(2,8x-4x=1208\)\(\Rightarrow4x=1208\Rightarrow x=302\)

\(3,x-382=159\div3\)\(\Rightarrow x-382=53\Rightarrow x=435\)

\(4,3x+30=402\)\(\Rightarrow3x=372\Rightarrow x=124\)

\(5,12x-13x-500=1500\)\(\Rightarrow-x-500=1500\Rightarrow-x=1000\Leftrightarrow x=-1000\)

a) \(2x\left(12x-5\right)-8x\left(3x-1\right)=30\)

\(24x^2-10x-24x^2+8x=30\)

\(-2x=30\)

\(x=-15\)

vay \(x=-15\)

b) \(3x\left(3-2x\right)+6x\left(x-1\right)=15\)

\(9x-6x^2+6x^2-6x=15\)

\(3x=15\)

\(x=5\)

a) x = -15

b) x= 5

b: \(\Leftrightarrow48x^2-12x-20x+5-48x^2+36x=30\)

\(\Leftrightarrow4x=25\)

hay \(x=\dfrac{25}{4}\)

a, 3x.(12x-4)-9x(4x-3)=30

=>36x²-12x-36x²+27x=30

=>5x=30

=> x=6

b,x.(5-2x)+2x.(x-1)=15

=> 5x-2x²+2x²-2x=15

=>3x=15

=>x=5

tk mk nha bn

*****Chúc bạn học giỏi*****

a) 3x . (12x - 4) - 9x(4x - 3) = 30

 3x . 12x - 12x - 9x.4x + 27x = 30

(3x . 12x - 9x . 4x) - (12x - 27x) = 30

(36x² -36x²) + 15x = 30

=> 15x = 30

=> x = 30 : 15

=> x = 2

b) x.(5 - 2x) + 2x.(x - 1) = 15

5x - 2x² + 2x² - 2x = 15

(5x - 2x) - (2x² - 2x²) = 15

=> 3x = 15

=> x = 15 : 3 = 5