a: \(A=8^2\cdot32^4=2^6\cdot2^{20}=2^{26}\)

b: \(B=27^3\cdot9^4\cdot243=3^9\cdot3^8\cdot3^5=3^{22}\)

a: \(A=\left(2^3\right)^2\cdot\left(2^5\right)^4=2^6\cdot2^{20}=2^{26}\)

b: \(=\left(3^3\right)^3\cdot\left(3^2\right)^4\cdot3^5=3^9\cdot3^8\cdot3^5=3^{22}\)

\(A=8^2.32^4=\left(2^3\right)^2.\left(2^5\right)^4=2^6.2^{20}=2^{26}\)

\(B=27^3.9^4.243=\left(3^3\right)^3.\left(3^2\right)^4.3^5=3^9.3^8.3^5=3^{22}\)

\(A=8^2.32^4=2^6.2^{20}=2^{26}\)

\(\Rightarrow2^{26}\)

\(B=27^3.9^4.243=3^9.3^8.3^5=3^{22}\)

\(\Rightarrow3^{22}\)

TL

a . x ∈ ∅                                                b . x=-10,                             x=-5177/5000,                               x=-10173/10000.

HT

bạn team ff và team fa lạc đề rồi

Huyền ơi cùng anh nào đấy kks

\(5x\cdot5x\cdot5x=\left(5x\right)^3\)

\(x^1\cdot x^2\cdot...\cdot x^{2006}=x^{2013021}\)

\(x\cdot x^4\cdot x^7\cdot...\cdot x^{100}=x^{1717}\)

\(x^2\cdot x^5\cdot x^8\cdot...\cdot x^{2003}=x^{669670}\)

Nếu đúng thì cho mình xin cái !!!

\(x^1\cdot x^2\cdot...\cdot x^{2006}=x^{\frac{\left(2006+1\right)2006}{2}}=x^{2013021}\)

\(x\cdot x^4\cdot x^7\cdot...\cdot x^{100}=x^{\frac{\left(100+1\right)\left(\frac{100-1}{3}+1\right)}{2}}=x^{1717}\)

\(x^2\cdot x^5\cdot x^8\cdot...\cdot x^{2003}=x^{\frac{\left(2003+2\right)\left(\frac{2003-2}{3}+1\right)}{2}}=x^{669670}\)

Hơi khó nhìn bn thông cảm!

a, \(3^4\) 

b,  \(8^7:8^2\) 

c,  \(x^3.x^2.x\)  

d,  \(4^n.4^2\)  

e, \(3^{k+2}:3^k\)  

a, 3^4

b,8^7:8^2=8^5

c, x^3.x^2.x=x^6

d,4^n.4^2=4^(n+2)

e, 3^k+2:3^k

=3^k.(1+2)

=3^k.3

=3^(k+10

Mấy bài này đẽ ẹc mà !!!

a) 3⁴

b) 8⁷ : 8² = 8 ^{7 - 2} = 8⁵

c) x³ . x² . x = x^{3 + 2 + 1} = x⁶ .

d) 4ⁿ . 4² = 4^{n + 2}

^e) 3^{k+ 2} : 3 ^k = 3^{k + 2 - k} = 3^k .

a) \(\dfrac{9}{4}-3y+y^2\)

\(=\left(\dfrac{3}{2}\right)^2-3y+y^2\)

\(=y^2-2\cdot\dfrac{3}{2}\cdot y+\left(\dfrac{3}{2}\right)^2\)

\(=\left(y-\dfrac{3}{2}\right)^2\)

b) \(x^3+6x^2y+12xy^2+8y^3\)

\(=x^3+6x^2y+12xy^2+\left(2y\right)^3\)

\(=x^3+3\cdot x^2\cdot2y+3\cdot x\cdot\left(2y\right)^2+\left(2y\right)^3\)

\(=\left(x+2y\right)^2\)

\(8^4.16^5.32=2^{3.4}.2^{4.5}.2^5=2^{12}.2^{20}.2^5=2^{12+20+5}=2^{37}\)

8⁴.16⁵.32=2^4.3.2^4.5.2⁵= 2^12+20+5=2²⁷

^{( nhớ tick đúng cho mình nha)}

8^4 . 16^5 . 32 = 2^3.4 . 2^4.5 . 2^5 = 2^12 . 2^20 . 2^5 = 2^37

a: 26⋅33=(22⋅3)3=12326⋅33=(22⋅3)3=123

b: 64⋅83=24⋅34⋅29=213⋅3464⋅83=24⋅34⋅29=213⋅34

c: 16⋅81=36216⋅81=362

d: 254⋅28=1004

\(x^4\cdot x^7\cdot...\cdot x^{100}\)

\(=x^{4+7+...+100}\)

\(=x^{52\cdot33}=x^{1716}\)

\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}\)

Ta có : \(x^1\cdot x^2=x^{1+2}=x^3\)

Tương tự : \(x^1\cdot x^2\cdot x^3=x^{1+2+3}=x^6\)

Áp dụng vào bài toán :

\(x^1\cdot x^2\cdot x^3\cdot...\cdot x^{2006}=x^{1+2+3+...+2006}\)

\(\Rightarrow x^{1+2+3+...+2006}=x^{2013021}\)

Sửa câu a : \(x^{1+2+3+...+2006}=x^{2033136}\)