Tính bằng cách thuận tiện nhất, rồi viết kết quả dưới dạng số thập phân:
a/\(\frac{2}{3}.\frac{3}{4}.\frac{4}{5}\)
b/\(\frac{1}{2}:\frac{3}{4}:\frac{5}{6}\)
Help me!
tính bằng cách thuận tiện nhất: \(6\frac{2}{7}+7\frac{3}{5}+8\frac{6}{9}+9\frac{1}{4}+\frac{2}{5}+\frac{5}{7}+\frac{1}{3}+\frac{3}{4}\)
TÍNH BẰNG CÁCH THUẬN TIỆN NHẤT
A)\(\frac{2}{3}\cdot\frac{4}{5}+\frac{1}{3}\cdot\frac{4}{5}=\)
B)\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\)
C)\(\frac{2}{3}\cdot\frac{4}{5}-\frac{1}{3}\cdot\frac{4}{5}=\)
D)\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}+\frac{1}{3}\right)=\frac{4}{5}.\frac{3}{3}=\frac{4}{5}.1=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}+\frac{1}{6}\right)=\frac{3}{4}:\frac{2}{3}=\frac{9}{8}\)
\(\frac{2}{3}.\frac{4}{5}-\frac{1}{3}.\frac{4}{5}=\frac{4}{5}\left(\frac{2}{3}-\frac{1}{3}\right)=\frac{4}{5}.\frac{1}{3}=\frac{4}{15}\)
\(\frac{1}{2}:\frac{3}{4}-\frac{1}{6}:\frac{3}{4}=\frac{3}{4}:\left(\frac{1}{2}-\frac{1}{6}\right)=\frac{3}{4}:\frac{1}{3}=\frac{9}{4}\)
\(\frac{2}{3}.\frac{4}{5}+\frac{1}{3}.\frac{4}{5}=\left(\frac{2}{3}+\frac{1}{3}\right).\frac{4}{5}=1.\frac{4}{5}=\frac{4}{5}\)
\(\frac{1}{2}:\frac{3}{4}+\frac{1}{6}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}+\frac{1}{6}.\frac{4}{3}=\left(\frac{1}{2}+\frac{1}{6}\right).\frac{4}{3}=\frac{2}{3}.\frac{4}{3}=\frac{8}{9}\)
c,d tương tự
A) \(\frac{2}{3}\). \(\frac{4}{5}\)+ \(\frac{1}{3}\). \(\frac{4}{5}\) B) \(\frac{1}{2}\). \(\frac{4}{5}\)+ \(\frac{1}{6}\): \(\frac{3}{4}\) C) \(\frac{2}{3}\). \(\frac{4}{5}\)- \(\frac{1}{3}\). \(\frac{4}{5}\)
= \(\left(\frac{2+1}{3}\right)\). \(\frac{4}{5}\) = \(\frac{2}{5}\)+ \(\frac{2}{9}\) = \(\frac{2}{3}\)- \(\frac{1}{3}\). \(\left(\frac{4-4}{5}\right)\)
= 1 . \(\frac{4}{5}\) = \(\frac{28}{45}\) = \(\frac{1}{3}\). 0
= \(\frac{4}{5}\) = 0
Tính: \(D=3\frac{5}{3}.20\frac{3}{41}-7\frac{3}{41}.3\frac{5}{41}+\left(-\frac{1}{2}\right)\)
Tính bằng cách thuận tiện nhất: \(\frac{2^{12}.3^5-4^6.3^6}{2^{12}.9^3+8^4.3^5}\)
Tính: \(F=-\frac{5}{\sqrt{196}}-\frac{5}{\left(2\sqrt{21}\right)^2}-\frac{\sqrt{25}}{204}-\frac{\left(\sqrt{5}\right)^2}{374}\)
3 câu này mình đều tính rồi nhưng kết quả cao hoặc k ra được đáp số, mong các bạn gíup đỡ!
Tính bằng cách thuận tiện nhất :
a) \(\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)
b) \(\frac{9}{13}+\frac{4}{13}+\frac{2}{3}\)
\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)
\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)
\(=1+\frac{1}{6}\)
\(=\frac{7}{6}\)
Hok tốt!~
\(\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)
\(=\frac{2}{5}+\frac{3}{5}+\frac{1}{6}\)
\(=\frac{5}{5}+\frac{1}{6}\)
\(=1+\frac{1}{6}\)
\(=1\frac{1}{6}=\frac{7}{6}\)
Tính bằng cách thuận tiện nhất:
\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)
\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)
\(=4-1\frac{3}{4}\)
\(=2\frac{1}{4}\)
\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)
\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)
\(=4-\frac{7}{4}\)
\(=\frac{16}{4}-\frac{7}{4}\)
\(=\frac{9}{4}\)
Tính bằng cách thuận tiện nhất :
\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
= \(6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}=6\frac{5}{7}-2\frac{5}{7}\)\(-1\frac{3}{4}\)= \(4-1\frac{3}{4}\)=\(\frac{9}{4}\)
47/7 - (7/4 + 19/7) =47/7 -125/28 =gomen =tao xin lỗi chịu rùi = <3
\(6\frac{5}{7}- \left(1\frac{3}{4}+2\frac{5}{7}\right)\)
\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)
\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)
\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{7}{4}\)
\(=\frac{28}{7}-\frac{7}{4}\)
\(=4-\frac{7}{4}\)
\(=\frac{16}{4}-\frac{7}{4}\)
\(=\frac{9}{4}\)
a)Tính bằng cách thuận tiện nhất :
\(\frac{1}{2}x\frac{1}{3}+\frac{1}{3}x\frac{1}{4}+\frac{1}{4}x\frac{1}{5}+\frac{1}{5}x\frac{1}{6}\)
b) Tính :
\(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)\)
\(a,\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=\frac{1}{2}-\frac{1}{6}=\frac{1}{3}\)
\(b,\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\)
\(=\frac{1\times2\times3}{2\times3\times4}=\frac{1}{4}\)
Tính bằng cách thuận tiện nhất:
\(\frac{1}{10}+\frac{2}{20}+\frac{3}{30}+\frac{4}{40}+\frac{5}{50}+\frac{6}{60}+\frac{7}{70}+\frac{8}{80}+\frac{9}{90}\)
\(=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+...+\frac{1}{10}\)có 9 p/số
\(=\frac{1}{10}.9=\frac{9}{10}\)
= 1/10 + 1/10 + ...................... + 1/10 có 9 phân số
= 1/10 x 9
= 9/10
ai tk mình mình đang bị âm điểm
9 / 12 bn nha
tk mk nha các bn
thanks nhiêu
Tính bằng cách thuận tiện nhất:
\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}\)
\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}=\left(\frac{1}{3}+\frac{4}{6}\right)+\left(\frac{1}{4}+\frac{9}{12}\right)+\left(\frac{1}{5}+\frac{16}{20}\right)\)
\(=1+1+1=3\)
Ta có\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}=\left(\frac{1}{3}+\frac{4}{6}\right)+\left(\frac{1}{4}+\frac{9}{12}\right)+\left(\frac{1}{5}+\frac{16}{20}\right)\)
\(=\left(\frac{2+4}{6}\right)+\left(\frac{3+9}{12}\right)+\left(\frac{4+16}{20}\right)\)
\(=\frac{6}{6}+\frac{12}{12}+\frac{20}{20}\)
\(=1+1+1\)
\(=3\)