Cho Efrac{100^2+1^2}{100.1}+frac{99^2+2^2}{99.2}+frac{98^2+3^2}{98.3}+...+frac{52^2+49^2}{52.49}+frac{51^2+50^2}{51.50}Cho Ffrac{1}{2}+frac{1}{3}+...+frac{1}{100}+frac{1}{101} ; ChoGfrac{1}{100.1}+frac{1}{99.2}+frac{1}{98.3}+...+frac{1}{52.49}+frac{1}{51.50}a,Tính: frac{E}{F} b,Tính: F-101GLàm giúpmìnhnha!Đangcầ...
Đọc tiếp
\(Cho\) \(E=\frac{100^2+1^2}{100.1}+\frac{99^2+2^2}{99.2}+\frac{98^2+3^2}{98.3}+...+\frac{52^2+49^2}{52.49}+\frac{51^2+50^2}{51.50}\)
\(Cho\) \(F=\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}+\frac{1}{101}\) \(;\) \(Cho\)\(G=\frac{1}{100.1}+\frac{1}{99.2}+\frac{1}{98.3}+...+\frac{1}{52.49}+\frac{1}{51.50}\)
\(a,Tính:\) \(\frac{E}{F}\) \(b,Tính:\) \(F-101G\)
\(Làm\) \(giúp\)\(mình\)\(nha!\)\(Đang\)\(cần\)\(!\)
